India vs Australia: Why Rinku Singh last-ball six wasn't counted?

Rinku Singh hit a six off the last ball in the thrilling first T20I between India and Australia on Thursday to guide Men in Blue to a 1-0 lead in the five-match series, but the maximum was not counted and the home team was only given one run. Are you confused? Let’s break down exactly what happened.

India needed seven off the last over in the 209-run chasse at the Dr. Y.S. Rajasekhara Reddy ACA-VDCA Cricket Stadium in Visakhapatnam. Rinku Singh was on strike and Sean Abbott was asked to bowl the final over.

Ball 1 and 2: Rinku started with a four over backward point and then took a bye after missing on a pull shot.

Two more runs were needed now.

Ball 3: Axar Patel came on strike and Abbott struck immediately with the all-rounder giving away a top-edge back to the bowler.

Ball 4: Ravi Bihsnoi missed a hook shot but Rinku ran for a bye as the former was run out at the non-striker’s end.

Ball 5: Rinku went hard to deep mid-wicket and asked for a two from his new partner Arshdeep Singh. However, Arshdeep fell short of his crease trying to complete the second run and had to go back to the hut. Three wickets fell on a trot but most importantly India collected one run and Rinku stayed on strike.

One run is needed now.

Ball 6: A fuller ball by Abbott is dispatched over long-on by Rinku for a six as India win the match by two wickets, but the six is not counted as it was a no-ball by the bowler and India completed the chase with the help of that one run.

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